Find a basis for the set of vectors in set of real numbers R cubed in the plane x minus 7 y plus 4 z equals 0. [Hint: Think of the equation as a "system" of homogeneous equations.] A basis for the set of vectors in set of real numbers R cubed in the plane x minus 7 y plus 4 z equals 0 is StartSet nothing EndSet .

Step-by-step explanation:

Any vector in this plane is actually a solution to the homogeneous system x-7y+4z = 0 (although this system contains only one equation). So we are to find a basis for the kernel of the coefficient matrix

A = x-7y+4z = 0

A =(1, -7, 4)

let x = 7y - 4z

  =

∴  form a basis for kernel A

a

step-by-step explanation:

when a number is between two straight lines it means the absolute value.

to find absolute value you need to know how many numbers is that number away from 0.

when finding absolute value the number will always come out positive

so absolute value of -3 is 3

absolute value of 3/2 is 3/2

absolute value of -2 is 2

absolute value of 3.5 is 3.5

absolute value of -1 is 1

now put these numbers in order:

a)   |-1|, |3/2|, |-2|, |-3|, |3.5|