Two times the sum of a number and 8 is twenty. What is the number?

The required value of n is 2.

We have to determine, two times the sum of a number and 8 is twenty. What is the number.

To obtain the number calculation must be done in a single unit;

Here,

Let the number be n,

And sum of number n and 8 is (n+8).

Therefore,

Two times sum of the number = 20

Hence, The required value of n is 2.

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n=2

2(n+8)=20

2n+16=20

     -16  -16

2n=4

/2   /2

n= 2

Hope this helps :)

δabc ≅ δdcb by sas because

db ≅ ac . . given (side)

bc ≅ bc . . reflexive property (side)

∠dbc ≅ ∠ acb . . alternate interior angles where transversal bc crosses parallel lines bd and ac (included angle)