Y= 4*x^2-32-20-16 pa= (x*SQRT(2)+a+b)/2 pb= (x*SQRT(2)+a+c)/2 pc= (x*SQRT(2)+d+c)/2 pd= (x*SQRT(2)+d+b)/2 pe= (x*(2)+c+b)/2 pf= (x*(2)+a+d)/2 SQRT(pa*(pa-a)*(pa-b)*(pa-x*SQRT(2) ))+x^2/2=32 SQRT(pb*(pb-a)*(pb-c)*(pb-x*SQRT(2) ))+x^2/2=20 SQRT(pc*(pc-d)*(pc-c)*(pc-x*SQRT(2) ))+x^2/2=16 SQRT(pc*(pc-d)*(pc-c)*(pc-x*SQRT(2) ))+x^2/2=y SQRT(pe*(pe-c)*(pe-b)*(pe-x*(2)))+2 *x^2+20+16=4*x^2 SQRT(pf*(pf-d)*(pf-a)*(pf-x*(2)))+2 *x^2=4*x^2

i can you with this question sweetie!

step-by-step explanation:

sas (side angle side)

aa(angle angle)

sss(side side side)

sas you have to find two sides with an angle in between

aa you find two angles because it will always add up to 180

sss find all sides

step-by-step explanation:

delaney would like to make a 5lb nut mixture that is 60% peanuts and 40% almonds.

she has several pounds of peanuts and several pounds of a mixture that is 20% peanuts and 80% almonds.

let 'p' represent the number of pounds of peanuts needed to make the new mixture, and  

let 'm' represent the number of pounds of the 80% almond-20% peanut mixture.

:

p + m = 5

therefore

m = (5-p)

write an equation based on the percent of peanuts

1p + .2m = .6(5)

replace m with (5-p)

p + .2(5-p) = .6(5)

p + 1 - .2p = 3

p - .2p = 3 - 1

.8p = 2

p = 2/.8

p = 2.5 lbs of peanuts required

then

5 - 2.5 = 2.5 lbs of the peanut/almond mixture required

:

a) what is the system that models this situation?

p + m = 5

1p + .2m = .6(5)