In ΔJKL, the measure of ∠L=90°, JK = 7.3 feet, and KL = 4.7 feet. Find the measure of ∠J to the nearest tenth of a degree.

40.0°

Step-by-step explanation:

Given the triangle ∆JKL with the following measure

∠L=90°, JK = 7.3 feet, and KL = 4.7 feet.

In order find the angle ∠J, we will use the concept of SOH CAH TOA.

Since we are looking for the angle ∠J, our opposite side will be the side facing the angle ∠J directly.

Hypotenuse = JK = 7.3ft

According to SOH:

Sin ∠J = Opposite/Hypotenuse

Sin∠J = 4.7/7.3

Sin∠J = 0.644

∠J = arcsin 0.644

∠J = 40.0° to the nearest tenth of a degree

the circle one

what? ?

what type of question is thiss

step-by-step explanation: