The surface areas of two similar solids are 441 cm² if the volume of the smaller solid is 250 cm³ what is the volume of the larger solid to the nearest cubic centimeter

The complete question is;

The surface areas of two similar solids are 441 cm² and 225 cm². If the volume of the smaller solid is 250 cm³ what is the volume of the larger solid to the nearest cubic centimeter

volume of the larger solid;V = 686 cm³

Step-by-step explanation:

We are given that;

Area of smaller solid = 225 cm²

Area of bigger solid = 441 cm²

Now, let r be the ratio of similarity;

Thus ratio of big to small solid is gotten from;

441 = 225 x r²

441/225 = r²

r =√441/225

r = 21/15 = 7/5

Now, let V be the volume of the larger solid.

Thus;

V = r³(250)

V = (7/5)³(250)

V = 686 cm³

-2x + 7 = 7

subtract 7 from both sides.

-2x = 0

divide both sides by -2.

x = 0