PLEASE I NEED HELP

Solve the system of equations.

–5x – 12y – 43z = –136
–4x – 14y – 52z = –146
21x + 72y + 267z = 756

Question options:

x = 6, y = 9, z = –6

x = 1, y = 3, z = 4

infinite solutions

no solution

no solution

Step-by-step explanation:

–5x – 12y – 43z = –136

–4x – 14y – 52z = –146

21x + 72y + 267z = 756

Every coefficient of the second equation is a multiple of 2, so divide both sides by 2.

Every coefficient of the third equation is a multiple of 3, so divide both sides by 3.

–5x – 12y – 43z = –136

–2x – 7y – 26z = –73

 7x + 24y + 89z = 252

Let's call the above system the "simplified original system."

Using the simplified original system, multiply the first equation by -2 and the second equation by 5. Then add them.

          10x + 24y + 86z = 272

(+)      -10x - 35x - 130z = 365

                   -11y - 44z = 637

Now we have an equation with only y and z.

Now, using the simplified original system, multiply the second equation by 7 and the third equation by 2. Then add them.

        –14x – 49y – 182z = –511

(+)       14x + 48y + 178z = 504

                     -y - 4z = -7

Now we have a system in 2 unknowns, y and z.

-11y - 44z = 637

-y - 4z = -7

Multiply the second equation by -11 and add to the first equation.

      -11y - 44z = 637

(+)     11y + 44z = 77

                 0 = 714

Since 0 = 714 is false, this system has no solution.

No solution

Step-by-step explanation:

answer: it's upside down and i can't read it

step-by-step explanation:

the answer is: d) o, f, and kr.

atomic radius of bromine (br) is 114 pm.

atomic radius of oxygen (o) is 73 pm.

atomic radius of fluorine (f) is 72 pm.

atomic radius of krypron (kr) is 112 pm.

the atomic radius of a chemical element is a measure of the size of its atom.

the atomic radius varies with increasing atomic number, but usually increases because of increasing of number of electrons.

the atomic radius decreases across the periods because an increasing number of protons, because greater attraction between the protons and electrons.