What can you tell about the mean of each
distribution?
The average cost of o dog's annual visit is about $76.10 less ot A New Leash
on Life Animal Clinic than the average cost for a dog's annual visit at No Ruff
Stuff Animal Hospital.
The overage cost of a dog's annual visit is about $76.10 more at A New Leash
on Life Animal Clinic thon the average cost of a dog's annual visit at No Ruff
Stuff Animal Hospital
The average cost of a dog's annual visit is about $19.35 more ot A New Leash
on Life Animal Clinic than the overage cost of a dog's annual visit at No Ruff
Stuff Animal Hospital
The average cost of a dog's annual visit is about $19.35 less at A New Leash
on Life Animal Clinic than the overage cost for a dog's annual visitat No Ruff
Stuff Animal Hospital

good luck on your studies! : )

david edward.

cant see photo

step-by-step explanation:

0 and 5 minutes

step-by-step explanation:

given that one morning eight buses arrive late by the number of minutes given below:

0 8 2 6 9 2 0 7 8

write these in ascending order

0   0 2 6 7 8 8 9

in the afternoon two more buses arrive at the bus stop say by x and y minutes late.

total number of buses = 10

median = average of 4th and 5th after arranging in ascending order

since 4th entry is 6, the values of x and y should be below 6

also given 0 is the mode so either x or y or both should be 0 because then only 0 gets the maximum frequency and hence mode

thus we have

0 0 0 2 6 7 8 8 9 and another unknown entry which is below 6.

since median is 3.5, we have the unknown entry to be 5 only because then only median =( 2+5)/2

thus the after noon buses were late by 0 and 5 minutes.

54/3 is 18 so 18 is your answer