A fair six-sided die is tossed twice. What is the probability of the first toss will be a number less than 3, and the second toss will be a number greater than 3?

1st toss: 3/6

2nd toss: 3/6

All: 1/2

Step-by-step explanation:

On the first toss, it would be 3/6 because it is out of 6. For the second toss, it is out of 6 again so it is still 3/6. Since you want to know what the probability is when it is tossed twice, we multiply it by 2 and get 6/12. Either way, it is equivalent to 1/2. I hope this helps. Please mark me brainliest because lots of people have scammed me. I really need it. Please and thank you!

i pretty sure it is

i can't solve unless i know what the line is

step-by-step explanation:

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