Find the area of the following composite figures

Open the picture
Thank you

I like area questions.

On the left we have a triangle, base apparently 9 cm, height 7 cm.

In the middle it's a 3 cm by 9 cm rectangle.

Then it's a parallelogram, base 9.  We have to figure out the height; it must be 16 - 7 - 3 = 6 cm.

Adding up the areas,

A = (1/2) 9×7 + 3×9 + 6×9 = 112.5 sq cm

112.5 sq cm

10a^3+277a^2-132a-792

step-by-step explanation:

(2a+11)(5a-12)(foil)

=10a^2-24a+55a-132 =10a^2+31a-132

(10a^2+31a-132)(a+6)

=10a^3+60a^2+31a^2+186a^2-132a-792 =10a^3+277a^2-132a-792

i hope this is what you are looking for : )