Write the absolute value inequality in the form
x−bc that has the solution set x<−5 or x>7

|x - 1 |> 6,

Step-by-step explanation:

First we find the distance between the two points

-5 to 7

7 - -5 =7+5 = 12

We find 1/2 that distance

12/2 = 6

So we are looking for a greater-than inequality  because we are looking for the outsides because we want a less than and a greater than

|x - b |> c,

The center is 6 to that is c

|x - b |> 6,

To find the value of b

Let x = 7

7 -b =6

b=1

|x - 1 |> 6,

We can check by using -5

|-5 - 1 |> 6,

|x - 1| > 6

Step-by-step explanation:

x < -5 or x > 7

b is the centre:

(-5+7)/2 = 1

c is the distance from the centre

7 - 1 = 6

Or

1 - (-5) = 6

Since it's an or case, inequality with the modulus would be >

|x - 1| > 6

1. 3.4/4

2. 0.8/7

3. 0.5 x 3

4. 0.9 x 6

5. 10.8

6. 2.35

7. 0.567

8. 9.35

9. 0.02

10. 0.06

11. 0.16

12. 0.42

13. 0.63

14. 5.6

15. 8.1

16. 9.9

17. 0.28

18. 0.48

19. 0.27

20. 0.49

21. 0.45

22. 0.72

23. 0.9

24. 0.88

25. 0.75

26. 0.16

27. 0.328

28. 0.495

29. 0.72

30. 1.068