The volume of pyramid A is 704 cm cubed and the volume of pyramid B is 297 cm cubed. If the pyramids are similar and the surface area of pyramid B is 153 cm squared, find the surface area of pyramid A.

Step-by-step explanation:

272 cm²

Step-by-step explanation:

Step 1

We have to find the scale factor

When given the volume of two solids, the formula for the scale factor is

V1/V2 = (Scale factor)³

The volume of Pyramid A is 704 cm³ and the volume of Pyramid B is 297 cm³

V1 = Pyramid A

V2 = Pyramid B

704/297 = (scale factor)³

We simplify the left hand side to simplest fraction

The greatest common factor of 704 and 297 = 11

704÷11/297÷11 = (scale factor)³

64/27 = (scale factor)³

We cube root both sides

cube root(scale factor)³ = cube root (64/27)

scale factor = (4/3)

Step 2

(Scale factor)² = S1/S2

S1 = Surface area of Pyramid A =?

S2 = Surface area of Pyramid B = 153 cm²

Hence,

(4/3)² = S1/153

16/9 = S1/153

Cross Multiply

S1 × 9 = 16 × 153

S1 = 16 × 153/9

S1 = 272 cm²

Therefore, the Surface Area of Pyramid A = 272 cm²

2. angles qrt and qst both measures 156 degrees.

step-by-step explanation:  

we have been given a diagram of a circle and we are told that measure of arc qvt is 156 degrees.  

we can see from our given diagram that angle qrt and angle qst subtends to arc qvt.

since we know that angles subtended by the same arc at the circumference are always equal.

by angle subtended by same arc theorem, measure of angle qrt and angle qst will be equal to the measure of arc qvt.

therefore, angles qrt and qst both measures 156 degrees and 2nd statement is the correct choice.

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