Henrique drew and labeled the net shown. He also labeled the areas of the left and right triangular sides. A net has a rectangle at the center and 4 triangles on the sides. The rectangle has a length of 10 inches and height of 4 inches. 2 triangles have a base of 10 inches and a height of 5 inches. The other 2 triangles have an area of 13.6 inches squared. Use Henrique's work and finish finding the areas of the faces. What is the surface area of the rectangular pyramid?

Step-by-step explanation:

The net has a rectangle at the center. The area of the rectangle is expressed as

Area = length × width

Area of the rectangle = 10 × 4 = 40 inches²

The formula for determining the area of each triangular face is expressed as

Area = 1/2 × base × height

The area of each face of the triangle that has a base of 10 inches and a height of 5 inches is

Area = 1/2 × 10 × 5 = 25 inches²

The surface area of the rectangular pyramid is

Area of rectangle at the center + area of the four triangular faces

Therefore,

The surface area of the rectangular pyramid =

40 + 2(25) + 2(13.6) = 117.2 inches²

what is the question here

step-by-step explanation:

option c) graph of line going through 1, 4 and 3, 10

step-by-step explanation:

let y equal to margo's coin collection

let x equal to number of years

at the begining x=0, y=1 → point=(x,y)→point=(0,1)

she adds 3 coins per year, then y=1+3x

at x=1, y=1+3(1)=1+3→y=4→point=(x,y)→point=(1,4)

at x=3, y=1+3(3)=1+9→y=10→point=(x,y)→point=(3,10)

the graph of line going through (1, 4) and (3, 10), then the option c is the correct.