Students traveling to France on a study abroad trip have varying levels of French proficiency. Of the students studying abroad, 5 students are fluent, 6 students are intermediate, and 2 students are beginners. If a single student is picked at random, what is the probability that the student is fluent or a beginner?

Provide the final answer as a fraction.

option a, c,d are correct.

step-by-step explanation:

from the given figure, it is given that z is equidistant from the sides of the triangle rst, then from triangle tzb and triangle szb, we have

tz=sz(given)

bz=zb(common)

therefore, by rhs rule,δtzb ≅δszb

by cpctc, sz≅tz

also, from δctz and δasz,

tz=sz(given)

∠tcz=∠saz(90°)

by rhs rule, δctz ≅ δasz, therefore by cpctc, ∠ctz≅∠asz

also,from δasz and δzsb,

zs=sz(common)

∠zbs=∠saz=90°

by rhs rule, δasz ≅δzsb, therefore, by cpctc, ∠asz≅∠zsb

hence, option a, c,d are correct.

idk this answer sorry cant on this one.

step-by-step explanation:

what does x eaqual

step-by-step explanation: