How would you describe the relationship between the real zeros and x-intercepts of the function y=log4^(x-2)

A. When you set the function equal to zero, the solution is x = 6; therefore, the graph has an x-intercept at x = 6.

B. When you substitute x = 0 into the function there is no solution; therefore, the graph will not have any x-intercepts.

C. Since there is an asymptote at x = 2, the graph will not have an x-intercept; therefore, the function will have no real zeros.

D. When you set the function equal to zero, the solution is x = 3; therefore, the graph has an x-intercept at x = 3.
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