Tennis balls are sold in cylindrical cans with the balls stacked one on top of the other. A tennis ball has a diameter of 6.7 cm. To the nearest cubic centimeter, what is the minimum volume of the can that holds a stack of 4 tennis balls

629.92

Step-by-step explanation:

The minimum volume of the can that can hold 4 tennis balls must have at least the same volume as 4 tennis balls.

The volume of one tennis ball, V =

where r = radius of the tennis ball

The diameter of a ball = 6.7 cm

Its radius will be = 6.7 / 2 = 3.35 cm

Volume, V, will be:

V = 157.48

Hence, the volume of 4 balls will be:

4 * V = 4 * 157.48 = 629.92

The minimum volume that the cylindrical can has to have is 629.92 .

solution:

the given function is ,

      =

the three roots of this quadratic function is , 0 ,8 and 10.all the roots are real and rational.

if a quadratic equation is of the form ,

sum of the roots = a + b +c= 0+8+10=18=  

product of roots taken two at a time = a b + b c+ c a = 0+80+0=80 =  

product of roots = a b c = 0=  

there are 11 doors in a hall starting from 0 to 11.the entry in the hall is permitted through gate number 0 and exit is allowed through only gate number 8 and 10.so, three roots(0,8,10) of quadratic function is given by entry and exit route of this hall.

gmt is 4 hrs ahead of edt so just add four hours to 1: 14: 20 (minutes and seconds stay the same)

gmt is 5: 14: 20

hope this !

~just a girl in love with shawn mendes