Suppose two parallel lines are cut by a transversal. What angle relationships describe congruent angles in this context?

Corresponding angles

Linear pair

Same-side interior angles

Same-side exterior angles

Alternate exterior angles

Alternate interior angles

Corresponding angles

Step-by-step explanation:

In elementary geometry the word congruent is often used as follows.

Two line segments are congruent if they have the same length.

Two angles are congruent if they have the same measure.

Two circles are congruent if they have the same diameter.

The eight angles that are produced as a result of two parallel lines are cut by a transversal will together form four pairs of corresponding angles. Corresponding angles are congruent. All angles that have the same position with regards to the parallel lines and the transversal are corresponding pairs.

The angle relations that describe congruent angles are:

i. Corresponding angles

ii. Alternate interior angles

Step-by-step explanation:

A transversal is a straight line drawn at an angle, while parallel lines are lines drawn in such a way that the will never meet, even when extended continouosly.

Now drawing a transversal to cut two parallel lines forms four angles with each line. These angles formed has some common properties or relations, when appropriate principles are applied.

Since the sum of all angle at a point is , and the sum of angle on a line is . Then, the corresponding angles and alternate interior angles formed are congruent angles.

Therefore, the angle relationships to describe congruent angles are; the corresponding angles and alternate interior angles.

i can you with this question sweetie!

step-by-step explanation:

the correct functions are

h(x) = 3x + 2  

g(x) = 2^x

step-by-step explanation:

i proceed to calculate the different values ​​of k (x)

case 1)  k(x) = g(x) ∘ h(x)

g(x) ∘ h(x)=g(h(x))

k(x) = [2]^[3x + > is the option  4. k(x) = 2^(3x + 2 )

case 2)  k(x) = g(x) + h(x)

k(x) = [2^x]+[3x + 2]=2^x+3x+> is the option  1.) k(x) = 2^x + 3x + 2

case 3)k(x) = h(x) ÷ g(x)

k(x) =  [3x + 2]/[2^x]=3x/(2^x)+2/(2^x)=3x*(2^-x)+2^(1-x)

is the option  3.)   k(x) = (3x)2^(-x) + 2^(-x + 1 )

case 4)k(x) = g(x) - h(x)

k(x) =  [2^x]-[3x + 2]=2^x-3x-> is the option  2.) k(x) = 2^x - 3x - 2 

case 5)  k(x) = g(x) × h(x)

k(x) = [2^x]*[3x + > is the option  5.) k(x) = 2^x(3x + 2)

case 6)k(x) = h(x) ∘ g(x)

h(x) ∘ g(x)=h(g(x))

k(x)=3*[2^x]+> is the option  6. k(x) = 3(2^x) +2