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Mathematics, 24.04.2020 05:02 oofoofoof1

Complete the work to solve for y: 2 5 ( 1 2 y + 5 ) βˆ’ 4 5 = 1 2 y βˆ’ 1 + 1 10 y 1.Distributive property: 1 5 y + 2 βˆ’ 4 5 = 1 2 y βˆ’ 1 + 1 10 y 2.Combine like terms: 1 5 y + 6 5 = 3 5 y βˆ’ 1 3.Subtraction property of equality: 6 5 = 2 5 y βˆ’ 1 Addition property of equality: 11 5 = 2 5 y 4.Division property of equality: What is the value for y?

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Complete the work to solve for y: 2 5 ( 1 2 y + 5 ) βˆ’ 4 5 = 1 2 y βˆ’ 1 + 1 10 y 1.Distributive proper...
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