To solve the system of equations below, grace isolated the variable y in the first equation and then substituted into the second equation. what was the resulting equation?

2y = 10 \ x^ 2 64 - y^ 2 36 =1

answer: standard form is ax^2 + bx + c = 0

step-by-step explanation:

standard form is ax^2 + bx + c = 0

(2x + 1)(x - 2) = 0

distribute to get into standard form

2x^2 - 4x + x - 2 = 0

2x^2 - 3x - 2 = 0

a = 2, b= -3, c = -2

a is your answer

answer: x=3 and y=4

step-by-step explanation: