Solve the following quadratic equations by completing the square.

y^2-14y+48=0

  y = 6 or 8

Step-by-step explanation:

1. Subtract the constant:

  y^2 -14y = -48

2. Add the square of half the y-coefficient:

  y^2 -14y +49 = -48 +49

Write as a square, if you like:

  (y -7)^2 = 1

3. Take the square root:

  y -7 = ±√1 = ±1

4. Add the opposite of the constant on the left:

  y = 7 ±1  =  6 or 8

The solution is y = 6 or y = 8.

b. would be the answer : )

step-by-step explanation:

step 1: add -16x to both sides.

16x−4y+−16x=64+−16x  

−4y=−16x+64

step 2: divide both sides by -4.

−4y /-4 = -16x + 64/-4

answer:   y=4x−16

hope i'm right

answer is b

step-by-step explanation: