Comparing Areas Suppose you have two squares, one of which is larger than the other. Suppose further that the
side of the larger square is twice as long as the side of the smaller square. If the length of the side of the smaller
square is a millimeters, give the area of each square.
The area of smaller sanare is
mm2
Powie

smaller square: a^2 millimeters.

larger square: 4a^2 millimeters.

Step-by-step explanation:

So all we need to know is the formula of a square:

---If we know a side length, the Area(square) is equal to the side x side or s^2

---So the smaller square has a side length of : "a"

         a x a or a^2 =(a^2 mm^2)

---So the larger square has 2 times the side length of smaller square: 2 x a

         2a x 2a = 4a^2 = (4a^2 mm^2)

Have a great day, and I hope this helps you ;D

step-by-step explanation:

i dont get