Solve 7w^2+28=84, where w is a real number

2 square root of 2 and -2 square root of 2

Step-by-step explanation:

it has 4

step-by-step explanation:

les

elee

fg

elle

fetish

ser

el

le

f

lent

clee hd

lg

ad

be

hu

te

see

te

ele

cele

her

t

errel

c

s​

option a, c,d are correct.

step-by-step explanation:

from the given figure, it is given that z is equidistant from the sides of the triangle rst, then from triangle tzb and triangle szb, we have

tz=sz(given)

bz=zb(common)

therefore, by rhs rule,δtzb ≅δszb

by cpctc, sz≅tz

also, from δctz and δasz,

tz=sz(given)

∠tcz=∠saz(90°)

by rhs rule, δctz ≅ δasz, therefore by cpctc, ∠ctz≅∠asz

also,from δasz and δzsb,

zs=sz(common)

∠zbs=∠saz=90°

by rhs rule, δasz ≅δzsb, therefore, by cpctc, ∠asz≅∠zsb

hence, option a, c,d are correct.