Enter the values for the highlighted variables that
show how to subtract the rational expressions
correctly
2/x^2- 36-1/x^2+6x=2/(x+6)(x-6)-1/x(x+a) =bx/(x+6)(x-6)x- x-c/(x+6)(x-6)x
=dx-x+e/(x+6)(x-6)x
=x+f/(x+6)(x-6)x
=g/x(x-6)

it is x=-4

step-by-step explanation:

x =-.20752

step-by-step explanation:

4^(x+2)=12

4^(x+2)=12

take the log base 4 on each side

log 4 (4^(x+2) = log 4(12)

we know log b(a^y) = y log b (a)

(x+2) log 4(4) = log 4 (12)

x+2 = log 4 (12)

we know   logb c = loga c/loga b

we want to convert to base 10   so a = 10

by default, we do not write the 10   c = 4   and b = 10

log4 10 = log 12/log 4

log4 10 = log 12/ log 4

x+2 = log 12/ log 4

subtract 2 from each side

x +2 -2 = log 12/ log 4 -2

x = 1.79248125 -2

x =-.20752

same question do you know the answer