PLEASE URGENT!

suppose company C produces packages of hazelnuts that are normally distributed with a mean of 93.5 individual hazelnuts and a standard deviation of 2.4 hazelnuts.
Company D produces packages of hazelnuts that are normally distributed with a mean of 95.9 individual hazelnuts and a standard deviation of 2.9 hazelnuts.

prove mathematically and explain which company is most likely to have a package with 91 hazelnuts.

please show work!

d

step-by-step explanation:

- "runner b is moving at a slower rate."

- "the graphs shown are graphs of distance(km) against time(min).

the slopes of this graphs are are given by:

slope = (change in y)/(change in x)

= (change in distance)/(change in time)

this is the formula for finding the speed. so, the slope of these graphs represent the speed of the runner.

taking each division in the graph to represent 1 on both axis:

runner a ⇒ speed = (2-0)/(1-0)

= 2/1

= 2 km/min

runner b ⇒ speed = (3-0)/(3-0)

= 3/3

= 1 km/min

this shows that   runner b is moving at a slower rate."

the correct answer is c

good luck love

1/8 is left? add a bit more info plz