"what are the missing reasons in the proof?
given: ▱abcd with diagonal line segment bd
prove: triangle abd is congruent to triangle cdb
statements:
line segment ab is parallel to line segment cd
angle abd is congruent to angle cdb
triangle abd is congruent to triangle cdb"

AB is ║ to CD( property of parallelogram)

∠ABD is congruent to ∠CDB( Angles opposite of equal sides are congruent)

BD=BD( Reflexive property),

Step-by-step explanation:

Given: ABCD is a parallelogram with diagonal line segment BD.

Proof: In ΔABD and ΔCBD,we have:

AB is parallel to CD( Property of paralleogram),

∠ABD is congruent to ∠CDB( Angles opposite of equal sides are congruent)

BD=BD( Reflexive property),

Therefore, ΔABD≅ ΔCBD,

a function could be identified in 3 ways either on a chart,graph, or ordered pairs. first a function is that each point has its own. the rule is that there can be many x's to one y but there can not be 2 x's at different y's. so on a graph when you put a straight line through the y's there should be one dot only to be a function.

step-by-step explanation: