A soccer ball was kicked in the air and follows the path h(x)=−2x2+1x+6, where x is the time in seconds and h is the height of the soccer ball. At what time will the soccer ball hit the ground?

help please

The soccer ball hit the ground after 2 seconds

Step-by-step explanation:

Given:  h(x) = −2x² + x + 6

where x is the time in seconds and h is the height of the soccer ball.

When the soccer ball hit the ground, h(x) = 0

so, −2x² + x + 6 = 0 ⇒ by multiplying the equation by (-1)

2x² - x - 6 = 0

So, (2x + 3) ( x - 2) = 0

So, 2x + 3 = 0 ⇒ 2x = -3 ⇒ x = -3/2  rejected because the time must be (+)

OR , x - 2 = 0 ⇒ x = 2 seconds

so, the soccer ball hit the ground after 2 seconds

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step-by-step explanation: