Of 800 people surveyed, 420 were male, and 325 had cell phones. Of those with cell phones, 200 were female. What is the probability that a person surveyed was either male or had a cell phone?

The probability that a person surveyed was either male or had a cell phone is 0.775.

Step-by-step explanation:

Denote the events as follows:

M = a person is male

F = a person is female

X = a person has a cell phone

Y = a person does not have a cell phone

The information provided is:

N = 800

n (M) = 420

n (X) = 325

n (X ∩ F) = 200

The remaining data is computed as follows:

            M            F         Total

 X       125        200        325

 Y       295        180        475

Total   420        380        800

The probability of the union of two events is given by:

Compute the probability of selecting a male as follows:

Compute the probability that a person had a cell phone as follows:

Compute the probability that a person is male and had a cell phone as follows:

Compute the probability that a person surveyed was either male or had a cell phone as follows:

Thus, the probability that a person surveyed was either male or had a cell phone is 0.775.

-232

step-by-step explanation:

x² + 11x + 18 < 0  

[-11 ± sqrt(121 - 72)]/2 = (-11 ± 7)/2  

solution: (-9, -2)

step-by-step explanation: