A triangle has vertices at B(-3,0), C(2.-1). D(-1, 2). Which transforffiation would produce an image with vertices B*(1, -2), C"(0,3). D"(3, 0)?

(x, y) - (x + 1, y + 1). (X, y) - (y, x)

(x, y) - (x + 1, y + 1), (x, y) - (-x, y).

(x, y) - (X. -y). (X. y) - (x + 2 y + 2)

(x, y) - (-x, y). (x, y) - (x + 2, Y + 2)

no not all of them.

step-by-step explanation:

some of them have a square base.

a

b

d

step-by-step explanation:

37/3

step-by-step explanation:

step 1: simplify both sides of the equation.

7x+8(x+

1

4

)=3(6x−9)−8

7x+(8)(x)+(8)(

1

4

)=(3)(6x)+(3)(−9)+−8(distribute)

7x+8x+2=18x+−27+−8

(7x+8x)+(2)=(18x)+(−27+−8)(combine like terms)

15x+2=18x+−35

15x+2=18x−35

tep 2: subtract 18x from both sides.

15x+2−18x=18x−35−18x

−3x+2=−35

step 3: subtract 2 from both sides.

−3x+2−2=−35−2

−3x=−37

step 4: divide both sides by -3.

−3x

−3

=

−37

−3

x=

37

3