A new golf bag has a compartment that is roughly a rectangular prism that has dimensions of 6 inches by 8 inches by 9 inches. How many golf balls will
fit in the compartment if a golf ball has a diameter of 1.7 inches? (Reminder: You can assume that for random packing space 190% of the volume of the
sphere is needed to pack the spheres and Volume of Sphere = 4/3 pim3)
21 balls
88 balls
63 balls
57 balls

The dimensions of the rectangular prism is 5 inches by 7 inches by 8 inches. Volume of the rectangular prism is expressed as

Length of the base × width of the base × height of the prism.

Volume = 5×7×8 = 280 inches ^2

Each golf ball has the shape of a sphere. The volume of a sphere is expressed as

Volume of sphere = 4/3πr^3

The golf ball has a diameter of 1.7 inches. It means that the radius of the golf ball is 1.7/2 = 0.85

Volume of each golf ball = 4/3 × 3.14×0.85^3

= 2.57 inches^3

The number of golf balls that will fit into the compartment would be

Volume if compartment/ volume of each golf ball. It becomes

280/2.57 = 109 golf balls

Step-by-step explanation:

binomial distribution

median= 2

range = 7-0 = 7

how to find median?

no. of term=28

median=(28+1)/2=14.5th term

the 14th and 15th term are 2, therefore the median is (2+2)/2 = 2

5x+10 is the correct one

hope this