Please Help

|x+3|, if x>5

|x+3| , if x>2

|6m-54|, if m<9

|y−x|, if y>x

|x+3|, if x=2

|x-3|, if x>5

|120+x|, if x<-120

|x-120|, if x<-120

|x-(-12)|, if x>-12

|x-(-12)|, if x<-12

|x-(-12)|, if x=-12

|x-:3|, if x>0

|x-:3|, if x<0

x-:3|, if x=0

sss (side, side, side)

sas (side, angle, side)

asa (angle, side, angle)

aas (angle, angle, side)

hl (hypotenuse, leg)

ruth is 6 years old

step-by-step explanation:

6 + 24 = 30,   so 6/30 = .2  

if you do 1/5 it also equals .2, so that is the answer.

c. y = 1/4 x + 5

step-by-step explanation:

first, put the equation of the line on the graph into slope-intercept form

(y = mx + b):   y = -4x + 8

second, a perpendicular line has to have "an opposite/reciprocal slope" to the original slope. so, find the "m" value in your original equation (it's -4, right? )

original slope: m = -4   perpendicular slope: change the sign to its opposite and find the reciprocal ("flip" the number)

new slope is now positive (b/c the original slope was negative 4), and it's 1/4 (not the original slope of 4 or 4/1)