Un triángulo isósceles ,la altura al lado desigual mide 1 cm mas que longitud de ese lado . Calcula el valor de dicha altura sabiendo que el area es de 6 cm²

Hence the required dimension is 4cm.

Step-by-step explanation:

Given:

An Isosceles triangle with uneven side=l+1 cm

Area= 6 sq cm

To Find:

Height of Triangle.

Solution:

We know that area of triangle given by,

Area=1/2*base*height.

Here height =1+base

6=1/2((b+1)*b

12=(b+1)*b.

b^2+b-12=0

(b-3)(b+4)=0

b=3 or b=-4

So length never be negative

so b=3 cm

And height=b+1=3+1=4 cm.

step-by-step explanation:

i think you should think about the question and not look online.

hello from mrbilldoesmath!

answer:   x^2 + y^2 = 1024

discussion:

the equation of a circle with center (h,k) and radius "r" is

(x-h)^2 + (y-k)^2 = r^2.

in our case

(x-0)^2 + (y-0) ^2 = 32^2 = 1024

you,

mrb