A hyperbola centered at the origin has a vertex at (-6, 0) and a focus at (10, ).

Vertices: (0,-a),(0,a)

Foci: (0,-c).(0.c)

Asymptotes: y==

Vertices: (-a,0),(a,0)

Foci: (-0,0),(0,0)

Asymptotes your

Directrices --

Standard Equation

Directrices

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Standard Equation

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Which are the equations of the directrices?

step-by-stp

the correct answer is the section c

area = length x width

length = 2 x width

32 = 2 x width x width

32 = 2 x width^2

36 = width ^2  

width = 6

length = 12

area is 32

perimeter = 2 x 12 + 2 x 6 = 24 + 12 = 36

step-by-step explanation:

cosine

step-by-step explanation:

step-by-step explanation:

a cube has 6 sides

the probability of getting 5 on the first cube is 1/6 since only one side of the cube has 5 on it.

there are 3 sides of the cube with even number on it [2,4,6]

therefore the probability of getting even number is 3/6

for both events to happen together, the probability would be

1/6 x 3/6 = 12/36

which simplifies to 1/12