Students in a marching band want to line up for their performance. The problem is that when they Line up in twos there is 1 left over. When they line up in threes there are 2 left over. When they line up in fours there are 3 left over. When they line up in fives there are 4 left over. When they line up in sixes there are 5 left over. When they line up in sevens there are no students left over. How many students are there?

x = 119

Step-by-step explanation:

Solution:-

- The number of students in a marching band = x

- When they Line up in "twos" there is 1 left over, That if we mathematically  express it:

                   Division: x / 2 , Remainder = 1

- When they Line up in "threes" there is 2 left over, That if we mathematically  express it:

                   Division: x / 3 , Remainder = 2

- When they Line up in "fours" there is 3 left over, That if we mathematically  express it:

                   Division: x / 4 , Remainder = 3

When they Line up in "fives" there is 4 left over, That if we mathematically  express it:

                   Division: x / 5 , Remainder = 4

When they Line up in "sixes" there is 5 left over, That if we mathematically  express it:

                   Division: x / 6 , Remainder = 5

When they Line up in "sevens" there are no left over, That if we mathematically  express it:

                   Division: x / 7 , Remainder = 0

- It means that the total number of "x" students are perfectly divisible by 7. If it is not divisible by 2, then it is an odd number.

- So,

                  x = 7 * a

Where,       x > 7 and exclude derivative multiples of (5, 4 , 6)

- So from trial and error, a = 17

                  x = 119  

the answer to the expression is 83

to determine the unit cost your would divide the total cost by the number sold.

7 bagels for $4.41       $4.41/7 = $.63 each at fresh side

5 bagels for $3.60         $3.60/5 = $.72 each at value mart