An object is launched straight into the air. The projectile motion of the object can be modeled using h(t) = 96t – 16t2, where t is the time since launch and h(t) is the height in feet of the projectile after time t in seconds.

Answer with Step-by-step explanation:

We are given that height of projectile after t seconds is given by

a.h(t)=144 ft

t-3=0

t=3

After 3 s, the height of the project will be 144 feet in the air.

b.h(t)=0

At t=0, the initial position of projectile

At t=6 s , the projectile will hit the ground.