In the figure below, \angle ABC∠ABCangle, A, B, C is inscribed in circle PPP. The length of \overline{PC} PC start overline, P, C, end overline is 121212 units. The arc length of \stackrel{\LARGE{\frown}}{AC} AC ⌢ A, C, start superscript, \frown, end superscript is \dfrac{68}{15}\pi 15 68 πstart fraction, 68, divided by, 15, end fraction, pi. What is the measure of \angle ABC∠ABCangle, A, B, C in degrees?

-3

step-by-step explanation:

a drawing really does here:

so i draw the horizontal line y=2 and the vertical line x=-2 at this intersection i put b (this is where my right angle is going to be).   so point b is at (-2,2).   point a is 5 units long and is also on y=2 so this point has to be (3,2) or (-7,2) -doesn't matter i will go with (3,2).

now we know c is at (-2,y) we don't know the y yet bet we know that c is on x=-2.

we have the area of the triangle is .5bh=12.5

we know the base length is 5 (ab)

we have the height is (2-y) if you look at your

plug in

.5(5)(2-y)=12.5

solve for y to get the y-coordinate for c

2.5(2-y)=12.5

divide both sides by 2.5 giving:

2-y=5

now subtract 2 on both sides

-y=3

y=-3

22.83 repeating

step-by-step explanation:

137 ÷ 6 is 22.8333333 therefore we understand that 3 is repeating.

happy to

pls mark as brainliest

answer: x=3 and y=4

step-by-step explanation: