A particle is moving along a projectile path at an initial height of 80 feet with an initial speed of 112 feet per second this can be represented by the function H(t) = 16t^2 + 112t + 80 what is the maximum height of this particle ?

A) 196 feet

B) 276 feet

C) 392 feet

D) 472 feet

7! = 7×6×5×4×3×2

3! = 3× 2

as 7! is multiple of 3! because 7! contains 3! that is 3× 2 as factor

so 7! /(3! ) = 7× 6× 5× 4

= 42 × 20

= 840

its b) 840✌✌✌

dhruv⭐

i think the answer is seven, for if i'm being useless °ω°

step-by-step explanation:

mean, 40.6

step-by-step explanation: