Which expression is equivalent to log18 – log(p + 2)?

log StartFraction p + 2 Over 18 EndFraction

log StartFraction 18 Over p + 2 EndFraction

log StartFraction 20 Over p EndFraction

log left-bracket 18 times (p + 2) right-bracket

log(18/(p+2))

log StartFraction 18 Over p + 2 EndFraction

Second option is the correct.

Step-by-step explanation:

There is a property of logarithms that when two logarithms are subtracting each other, we can make a single logarithm with the argument being the division of their arguments:

log(x) - log(y) = log(x/y)

So, with we have log18 – log(p + 2), we can rewrite as:

log18 – log(p + 2) = log(18/(p+2)), that is:

log StartFraction 18 Over p + 2 EndFraction

Second option is the correct.

the inequality is:

250c+180g≥950

step-by-step explanation:

let c denotes the number of days in a week   miyoko worked as a cryptographer.

and g denotes the number of days in a week she works as a geologist.

now we are given that she earns $250 for every day she works as a cryptographer,and earns $180 for every day she works as a geologist.

now miyoko's goal is to earn more than $950 this week.

hence, the inequality could be represented as:

250c+180g≥950