Please help asap

brainliest answer and five star rating

Here are three systems of equations. Which method (graphing, substitution, elimination) would you choose to solve and why. Use each method only once.

System #1 System #2 System #3

2x + 3y = 12 y = 2x +1 x = 2y + 5
4x + 3y = 18 y =-3x -2 x + 3y = 25

System #1

2x + 3y = 12   and  4x + 3y = 18

I'd use elimination on this one; we subtract equations and the 3y disappears,

2x = 6

x = 3

3y = 18-4x = 18 - 4(3) = 18 = 12 = 6

y = 2

System #2

y = 2x +1  and  y =-3x -2

Here I'd use elimination; we have two things equal to y, we eliminate y by setting the right sides equal to each other,

2x + 1 = -3x - 2

5x = -3

x = -3/5

y = 2x+1 = -1/5

check y=-3x -2 = 9/5 - 10/5 = -1/5, good

System #3

x = 2y + 5  and x + 3y = 25

Here I'd use substitution.   The first equation is for x in terms of y; if we substitute it into the second equation we'll just have an equation in y.

(2y + 5) +3y = 25

5y + 5 =25

5y = 20

y = 4

x = 2y+5 = 13

let's add {f(x)=x+1}f(x)=x+1 and {g(x)=2x}g(x)=2x together to make a new function.

f(x)+g(x) =(x+1)+(2x)=x+1+2x=3x+1

let's call this new function hh. so we have:

{h(x)}={f(x)}+{g(x)}{=3x+1}h(x)=f(x)+g(x)=3x+1

we can also evaluate combined functions for particular inputs. let's evaluate function hh above for x=2x=2. below are two ways of doing this.

method 1: substitute x=2x=2 into the combined function hh.

h(x)

h(2)

​    

=3x+1

=3(2)+1

=7

​ since h(x)=f(x)+g(x)h(x)=f(x)+g(x), we can also find h(2)h(2) by finding f(2) +g(2)f(2)+g(2).

first, let's find f(2)f(2):

f(x)

f(2)

​    

=x+1

=2+1

=3

​  

now, let's find g(2)g(2):

g(x)

g(2)

​    

=2x

=2⋅2

=4

​  

so f(2)+g(2)=3+4=\greend7f(2)+g(2)=3+4=7.

notice that substituting x =2x=2 directly into function hh and finding f(2) + g(2)f(2)+g(2) gave us the same answer!

a orange at the grocery store idk what other product that could be