Write a vector equation of the line that passes through P(-1,6) and is parallel to ä =(3, -1)?
a (x+7, + 8) = 4(5, 1)
c. (x+1, 7–6) = (3, - 1)
B. (X-5, y -14) =t(8,5)
d. (x + 14, y+ 13) = t(-1,8)

So the first thing we do is to multiply the top equation by 3. the reason i want to do this is i notice there will be a 6y on both equations and can possibly add/subtract them. so we get 6y = -3x + 27. adding that and the second equation we get 6x = 27-15 which is 12. divide by 6 and we get 2. ∴ x = 2. substituting 2 into the first equation we get 2y = -2 + 9 which is 7. divide by 2 and we get 7/2. ∴ y = 7/2, x = 2.