There are ten candidates for a job. The search committee will choose three of them, and rank the chosen three from strongest to weakest. How many different outcomes are possible

720

Step-by-step explanation:

Since we are choosing a subset of 3 people from a set of 10 people, and arranging the 3 people according to relative strength, the answer can be obtained by computing P(10,3).

 P(10,3)=10! / (10-3)!

= 10!/7!

Rewrite  10 !  as  

10 * 9  * 8  * 7 !  / 7!

Cancel the common factor of  7 !  and divide ( 10  * 9 * 8 ) by  1

10  * 9  * 8 = 720

δabc ≅ δdcb by sas because

db ≅ ac . . given (side)

bc ≅ bc . . reflexive property (side)

∠dbc ≅ ∠ acb . . alternate interior angles where transversal bc crosses parallel lines bd and ac (included angle)