HELP ME PLEASE HURRY: Wade has claims that quadrilateral ABCD is a square because he has found that all four sides are congruent as shown below:

AB = 8.3 units

BC = 8.3 units

CD= 8.3 units

AD = 8.3 units

Explain in at least two sentences why Wade is incorrect and what else he needs to show for ABCD to be a square. Be specific!

At first we should know that:

The properties of the square are:

It has four equal sides.All angles are right angles or equal to 90º.The sum of its all angles is 360ºIt has two pairs of perpendicular lines.It has two pairs of parallel lines.

The properties of Rhombus

It has equal four sides.The opposite sides are of the same length.It has two acute angles and two obtuse angles.The sum of its all angles is 360ºIt has zero pairs of perpendicular lines.It has two pairs of parallel lines.

So, Wade is incorrect because the quadrilateral may be Rhombus

And the quadrilateral to be a square, she needs to show that It has two pairs of perpendicular lines.