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Mathematics, 22.04.2020 18:10 justiceharris8

The center of a circle is located at (3, -4). The radius of the circle is 6.

What is the equation of the circle in general form?
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x2 + y2 − 6x + 8y − 11 = 0

x2 + y2 − 6x + 8y + 19 = 0

x2 + y2 + 6x − 8y − 11 = 0

x2 + y2 + 6x − 8y + 19 = 0

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The center of a circle is located at (3, -4). The radius of the circle is 6.

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