Suppose that time spent on hold per call with customer service at a large telecom company is normally distributed with a mean µ = 8 minutes and standard deviation σ = 2.5 minutes. If you select a random sample of 25 calls (n=25), What is the probability that the sample mean is between 7.8 and 8.2 minutes?

0.3108 is the probability that the sample mean is between 7.8 and 8.2 minutes.    

Step-by-step explanation:

We are given the following information in the question:

Mean, μ = 8 minutes

Standard Deviation, σ = 2.5 minutes

Sample size, n = 25

We are given that the distribution of  time spent is a bell shaped distribution that is a normal distribution.

Formula:

Standard error due to sampling =

P(sample mean is between 7.8 and 8.2 minutes)

0.3108 is the probability that the sample mean is between 7.8 and 8.2 minutes.

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susie has 7 apples