A rectangle has a length of 14cm and a diagonal of 17cm. What is the perimeter of the rectangle.

P ≈ 47.28

Formula for Perimeter of a Rectangle

P = 2l + 2w

Pythagorean Theorem.

a² + b² = c²

c² - a² = b²

c² - b² = a²

c = hypotenuse

b, and a = legs

With that out of the way we're ready to solve

To do this we'll use the Pythagorean Theorem

c² - b² = a²

Here we plug 17 in for c and 14 in for b to get a

  17² - 14² = a²

289 - 196 = a²

           93 = a²

        √93 = √a²

          = a

Here we'll use the perimeter formula for a rectangle

P = 2l + 2w

P = 2(14) + 2()

P = 28 + 2

P ≈ 47.28

g = (2, 2)

step-by-step explanation:

given the ratio is 1 : 1 then f is the midpoint of eg

let the coordinates of g = (x, y)

using the midpoint formula

(0 + x) = 1 ( multiply both sides by 2 )

0 + x = 2 ⇒ x = 2

similarly

(4 + y) = 3 ( multiply both sides by 2 )

4 + y = 6 ( subtract 4 from both sides )

y = 2

coordinates of g = (2, 2)