How does the shape of y=1/2(x-4)^2+1 compare to the shape of the quadratic parent function? Be specific. describe what effect the a -value has on the parabola. compared to the quadratic parent function, the shape of y=1/2 (x-4)^2+1 is because the a - value .

p ÷ r = tan(x)

step-by-step explanation:

given that there is a figure below shows a right triangle: a right triangle is shown with hypotenuse equal to q units and the length of the legs equal to p units and r units.

graph is missing so i will create the graph as per given information.

the angle between the legs having lengths p units and q units is y degrees. the angle between the legs having lengths r units and q units is x degrees.

now we need to find about what is p ÷ r equal to.

so we can use trigonometric ratio tan(x)=[altitude]/[base] to find the value of p ÷ r, because p is the altitude and r is the base.

p ÷ r=tan(x)

hence final answer is p ÷ r=tan(x).

it is a secret for it not to be compromised sorry

step-by-step explanation: