Can someone help solve for X

x = 2sqrt(5)

Step-by-step explanation:

We can use the Pythagorean theorem to solve

The legs are x and 8/2 =4

and the hypotenuse is 6

a^2 + b^2 = c^2

x^2 +4^2 = 6^2

x^2 +16 = 36

Subtract 16 from each side

x^2 +16-16=36-16

x^2 = 20

Take the square root of each side

sqrt(x^2) = sqrt(20)

x = sqrt(4*5)

x = sqrt(4) sqrt(5)

x = 2sqrt(5)

Step-by-step explanation:

check the picture below.

well, the angle at the vertex d is clearly not a right-angle, let's check for the one at the vertex f which does look like,   however if it's indeed, that means ef is perpendicular to df, in which case their slopes will be negative reciprocal of each other.

so the negative reciprocal of the slope of ef is 1, however the slope of df is not 1, is 1/2, so nope, they're not perpendicular lines.