Prove: The square of a number that is
two more than a multiple of 3 is one more
than a multiple of 3.
(3n + 2)2 = 9n2 + 12n +4
= [ ? ]n2 + ]n+ ] +1
= [ [ ]n2 + [ ]n + 1) + 1
= 1 more than a multiple of 3

answer rather than having to add and subtract the measurements of the semi-circle, notice that the semicircle to the left of ad is actually identical in area to the blank semicircle-shaped space to the left of bc. so if we transferred the red semicircle into the blank space, we would end up with a square of side length 24 cm. the area of a square is s^2 = 24^2 = 676 cm^2.

u also answered this so i think u would know but i am here to

put in or use mine

answer: answer is c!

ok i got to organize the

3/15 and 12/55

3*

aha

3*4 equals 12 but not

a: no

b:

8/24 12/35

no

gautie

it's c

5/18 = 25/90

5*5=25

18*5 = 90

hope that you!

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step-by-step explanation:

whats the