How would you explain the relationship between the real zero(s) of the function and x-intercept(s) of the graph? Since the graph crosses the x-axis at x = – 2, the function has a real zero of x = – 2. Since the graph never crosses the x-axis, the function has no real zeros. Since the graph eventually crosses the x-axis, the function has a real zero. Since the graph crosses the y-axis at 1/9, the function results in a real zero of x = 1/9?.

answer: 8d

step-by-step explanation:

45+5= 50+5=55+5=60

c

step-by-step explanation:

there is vertical asymptote at x = 2 and x = 0

vertical asymptote occurs at the points where the denominator is 0. so we can say that

x = 2 occurs when there is a factor (x-2) in the denominator, and

x = 0 occurs when there is a factor "x" in the denominator

thus, the denominator of the equation would have "x * (x-2)", this is option c only. that's the correct answer.

first, you divide the triangle in two, tô form a retangle triangle. after, using pythagoream theorem:

18^2 = 14^2 + (x/2)^2

(x^2/4) + 196 = 324

x^2/4 = 324 - 196

x^2/4 = 128

x^2 = 512

x = √512

x = √2^9

x = 16√2 cm

i hope i you.

37 = ending with 7

unit's digit in the cube..3

56 = ending with 6

unit's digit in the cube..2

133 = ending with

unit's digit in the cube..7

hope it : ( : )