What is the solution to the system of equations 2x + 3y = 40 and y = x + 10?
x = 2; y = 12

x = 4; y = 14

x = 12; y = 2

x = 14; y = 4

x=2, y=12

STEP BY STEP-

Replace the Y in 2x+3y=40 for X+10, because y=x+10. You now have 2x+3(x+10)=40. Now multiply the X and the 10 by 3, so you have 2x+3x+30=40. Combine like terms to get 5x+30=40. Subtract the 30 on both sides so you get 5x=10. Divide by 5 and that gives you the solution for X (2). Then, plug 2 in for X in the equation y=x+10. You now have Y=2+10. Combine like terms and you get 12, so Y=12.

Sorry that I'm so bad at explaining things

just take the area of the square and then the area of the circle then subtract the circle area from the squares area

step-by-step explanation: