Let A be the matrix v1 v2 v3 v4 v5 . Observe that Span{v1, v2, v3, v4, v5} = Col(A). Use this fact to compute a basis for Span{v1, v2, v3, v4, v5}. (Recall you can enter A into MATLAB as A = [v1 v2 v3 v4 v5].) (c) ? Translate your previous answer into a basis for W (consisting of polynomials). What is dim W?

okay..i will pick 8!

answer: (-8,4) are the coordinates of a

step-by-step explanation:

let the side of square abcd is x .

thus the area of square abcd is .

now, by the diagram area of triangle ead= 1/2 × ea × ad = 1/2 × ea × x

( because ad is the side of square)

and, according to the question,

the areas of square abcd and right ead are equal.

⇒

⇒ea=2x

thus, ea: ab=2: 1

therefore, point a divides line segment eb into the ratio 2: 1.

⇒ by sectional formula coordinates of a are,

=

=

=(-8, 4)

thus the coordinates of a are (-8,4)

correct answer was 0.5

x:       y:  

-1         4

0         4

1         6

2         18

3         20