What is the surface area for this right circular cylinder with a base of 36 cm2 and a height
of 12 cm?
A.)452.16cm2^
B.)489.84cm2^
C.)678.24cm2^
D.)3391.2cm2^

< coa = 150 ( given)

as ba and bc are tangents

so oc and oa is perpendicular to cb and ab respectively because in circle normal passes through centre

so in quadrilateral oabc

< coa + < oab + < ocb + < abc = 360

150 +90+90 + < abc = 360

330 + < abc = 360

< abc = 360 -330 = 30

so < abc = 30

⭐dhruv⭐

answer: dead jah

step-by-step explanation:

bullet + jah= dead jah

answer: the correct answer is -32

step-by-step explanation: